Hello ...
Sorry for the late post, but here's what we did on Friday.
First off, we went through the homework that were given on Thursday.
w + l + h = 80 cm
Length=10cm less than twice the sum of width and height and twice the width exceeds the height by 6 cm. Find the width, length and height of the box.
~We didn't go over the procedure on how to solve this problem, but the answers were:
h = 18cm, w = 12 cm, l = 50 cm
Then there was the question from the book (Ex. 25 #1) Letter "c" was done by Ramina on the white board. For those who didn't get to copy the procedure, here it is...
1. a) 3x4y+5z=2
4x+5y3z=5
5x3y+2z=11
(3) 3x4y+5z=2 (3)
(5) 4x+5y3z=5 (5)
9x12y15z=6
+ 20x+25y15z=25
ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ
29x+13y=19
(2) 4x+5y3z=5 (2)
(3) 5x3y+2z=11 (3)
8x+10y6z=10
+ 15x9y+6z=33
ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ
23x+y=43
29x+13y=19
(13) 23x+y=43 (13)
29x+13y=19
+ 229x+13y=559
ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ
270x = 540
ˉˉˉˉˉˉ ˉˉˉˉˉ
270 270
x = 2
29x+13y=19
29(2)+13y=19
58+13y=19
13y=5819
13y=39
ˉˉˉ ˉˉˉ
13 13
y = 3
3x4y+5z=2
(3)(2)4(3)+5z=2
612+5z=2
18+5z=2
5z=18+2
5z = 20
ˉˉˉ ˉˉˉ
5 5
z = 4
After this, we talked about a little something new called Circle Hyperbola.
It looks like this ...
A Circle Hyperbola can only have 0, 1, or 2 intercepts and no more than that. We can find the intercept by putting the equation on our calculator OR solve it algebraically. We did some examples as a practice on finding the intercepts of Circle Hyperbola.
► y=x1
y=x²6x+9
x1=x²6x+9
10=x²7x
x²7x+10=0
(x5) (x2)
x=5 x=2
y=4 y=1
another example was...
►x²y²=5
xy+6=0
y²=x²5 → y= √x²5 (#1)
y=6/x (#2)
6/x=√x²5
(6/x)² = (√x²5)²
36/x² = x²5
x^45x²=36 (substitute x^4 to u=x²)
u²5u36=0
(u9) (u=4)
u=9, 4
x²=9, 4
x=±3
x=3 , y=2
x=3 , y=2
After doing these examples, there were homework that were assigned for us to do. Exercise 26 (# 15) Also, don't forget to hand in your bonus mark homework sheets before Dr. Eviatar leaves!



Next Scribe ... Jamie
Sunday, November 9, 2008
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